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I D 1 uniform ( 450 , 550 ) I U 1 uniform ( 0.98 110 p 110 , 3 I D 1 p 110 ) R C 1 = 0 S 1 = N I D 1 I U 1 ln ( β 1 ) uniform ( ln ( 2.75 D ) , ln ( 3.3 D ) ) R e , 1 = exp ( ln ( β 1 ) ) S 1 D N ξ 1 = exp ( ln ( β 1 ) ) S 1 I U 1 + I D 1 N

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\begin{align*} ID_1 & \sim \text {uniform}(450,550) \\ IU_1 & \sim \text {uniform}(0.98\frac{110}{p}-110, 3\frac{ID_1}{p}-110) \\ RC_1 & = 0 \\ S_1 & = N - ID_1 - IU_1\\ \ln (\beta _1) & \sim \text {uniform}(\ln (\frac{2.75}{D}), \ln (\frac{3.3}{D})) \\ R_{e,1} & = \exp (\ln (\beta _1))\frac{S_1D}{N}\\ \xi _1 & = \exp (\ln (\beta _1))S_1\frac{IU_1 + ID_1}{N} \end{align*}